PRINCIPIA · THEOREM

Parallel ⇒ alternate interior angles equal

Dependencies: Parallel ⇒ corresponding angles equal (B.05, which grabs the corresponding angles for us), and Vertical angles are equal (to flip a corresponding angle into an alternate interior angle at QQ).

Statement

Let 12\ell_1 \parallel \ell_2 be cut by a third line tt: tt meets 1\ell_1 at PP and 2\ell_2 at QQ. The two angles between 1\ell_1 and 2\ell_2 carved out by tt, lying on opposite sides of tt, form a pair of alternate interior angles. The two such pairs are respectively equal.

Let α\alpha denote a corresponding angle at PP (the angle formed on a specified side by 1\ell_1 and tt), let β\beta be the corresponding angle at QQ on the same side as α\alpha, and let γ\gamma be the vertical angle to β\beta (i.e. the one at QQ that forms an alternate interior pair with α\alpha). Then

γ=α.\gamma = \alpha.

Two parallel lines \ell_1 \parallel \ell_2 cut by transversal t: the alternate interior angles \alpha at P and \gamma at Q are equal

Proof

The whole proof is just B.05 + vertical angles in two steps.

Step 1 (corresponding angles equal): by Parallel ⇒ corresponding angles equal, α=β\alpha = \beta.

Step 1: B.05 gives \alpha at P = the corresponding \beta at Q

Step 2 (alternate and corresponding are vertical to each other): at QQ, both β\beta and γ\gamma have QQ as their vertex, and their sides are given by the two opposite rays from QQ along 2\ell_2 together with the two opposite rays from QQ along tt — this is exactly the definition of vertical angles. By Vertical angles are equal, γ=β\gamma = \beta.

Step 2: at Q, \beta and \gamma are vertical to each other ⇒ \beta = \gamma; chain with Step 1 to get \gamma = \beta = \alpha

Together, γ=β=α\gamma = \beta = \alpha. \blacksquare

Immediate consequences

  • An alternate route to Parallel ⇒ co-interior angles supp. (B.07): from γ=α\gamma = \alpha, plus the fact that the co-interior and alternate interior angles at QQ form a linear pair (Linear pair sums to 180°), we immediately get α+βco-int=180\alpha + \beta_{\text{co-int}} = 180^\circ.
  • The core lemma for the angle sum of a triangle = 180180^\circ: drawing through one vertex of the triangle a line parallel to the opposite side, this theorem is the unique tool that "transports" the three interior angles onto that parallel line.
  • Construction ≡ algebraization of geometry: equal alternate interior angles let us copy any angle on 1\ell_1 to 2\ell_2 for free — together with the angle conditions of SSS / SAS, this is the entry point for many proofs of parallelogram properties, similar triangles, the Basic proportionality (intercept theorem) theorem (BPT), and so on.

Remarks

B.05 grabs the corresponding angles; this theorem flips them in place; pushing on to B.07 only needs one more linear pair. The three twin theorems (B.05 / B.06 / B.07) share the same "angle name converter" — that is why subsequent proofs cite them together so often.

Euclid's Elements I.29 lumps "equal alternate interior angles" and "equal corresponding angles" into a single proposition, and uses contradiction (assume not equal ⇒ co-interior angle sum <180<180^\circ ⇒ the fifth postulate forces the lines to meet ⇒ contradiction). We split it into the three layers B.05 → B.06 → B.07; each layer is a direct construction, making the dependency chain unidirectional and contradiction-free.

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