The three altitudes of a triangle meet at one point (orthocenter)
Dependencies: Through a point off a line, exactly one parallel exists (Playfair) (Through a point off a line, exactly one parallel exists (Playfair)), opposite sides of a parallelogram are equal (Parallelogram properties (opposite sides equal, diagonals bisect each other)), Three perpendicular bisectors meet (circumcenter) (Three perpendicular bisectors meet (circumcenter)).
Statement
Let . Drop a perpendicular from each of , , to the line containing the opposite side; the three perpendiculars (i.e. the three altitudes) meet at a single point. This point is called the orthocenter of , denoted .

Sign in to unlock the full proof
The first 20 theorems are free to read; this one and the rest require an account to see the full proof, animation, and consequences. Free, email-code sign-in only.
Sign in to unlock