PRINCIPIA · THEOREM

Angle bisector ⇔ equidistant from sides

Dependencies: SAS congruence. At this layer we prove only the forward direction: the converse (equidistant from the two sides ⟹ on the angle bisector) is deferred until after HL (hypotenuse-leg) congruence.

Statement

Angle bisector: let AOB\angle AOB be a nonzero, non-straight angle. If a ray OMOM lies inside AOB\angle AOB and satisfies

AOM=MOB,\angle AOM = \angle MOB,

then OMOM is called the angle bisector of AOB\angle AOB — the "half-angle" real number provided by axiom III (Protractor axiom) corresponds to exactly one such ray, which exists and is unique.

Distance from a point to a line: let \ell be a line and PP a point not on \ell. By axiom III, the foot of the perpendicular from PP to \ell is unique; call it EE. Then distance dist(P,):=PE\operatorname{dist}(P,\ell) := |PE|.

The complete biconditional —

let PP be a point inside AOB\angle AOB distinct from OO, and drop perpendiculars from PP to OAOA and OBOB with feet EE and FF respectively. Then

P lies on the angle bisector of AOBPE=PF.P\ \text{lies on the angle bisector of}\ \angle AOB \quad\Longleftrightarrow\quad |PE| = |PF|.

This section proves only the forward direction (\Rightarrow): PP on the angle bisector PE=PF\Rightarrow |PE|=|PF|. The converse (\Leftarrow) must wait until after HL; the reasons are in On the converse.

Angle-bisector property: P lies on the bisector OM of \angle AOB, E, F are the feet of perpendiculars from P to OA, OB respectively; then |PE| = |PF|

First 20 free · sign in for #21 onward

Sign in to unlock the full proof

The first 20 theorems are free to read; this one and the rest require an account to see the full proof, animation, and consequences. Free, email-code sign-in only.

Sign in to unlock
Help me make this theorem better