PRINCIPIA · THEOREM

Exterior angle equals the sum of two non-adjacent interior angles

Dependencies: Triangle interior angles sum to 180°, Linear pair sums to 180°.

Statement

Let ABC\triangle ABC have side BCBC extended along its original direction to a point DD (so that CC lies between BB and DD). Call ACD\angle ACD the exterior angle of ABC\triangle ABC at vertex CC, denoted γ\gamma'. Then

γ=A+B.\gamma' = \angle A + \angle B.

Exterior-angle identity: in \triangle ABC, extend BC to D; the exterior angle \gamma' is exactly tiled by \alpha + \beta

First 20 free · sign in for #21 onward

Sign in to unlock the full proof

The first 20 theorems are free to read; this one and the rest require an account to see the full proof, animation, and consequences. Free, email-code sign-in only.

Sign in to unlock
Help me make this theorem better