PRINCIPIA · THEOREM

Reflection: axis ⊥ bisects each pair of corresponding points

Depends on: Perpendicular bisector ⇔ equidistant from endpoints, SSS congruence.

Statement

Let \ell be a line in the plane, and denote by σ\sigma_\ell the reflection across \ell: each point PP maps to P=σ(P)P' = \sigma_\ell(P) such that \ell is the perpendicular bisector of segment PPPP' — this is the geometric definition of reflection.

Then σ\sigma_\ell preserves distances and angles: for any pair of points AA, BB and their images A=σ(A)A' = \sigma_\ell(A), B=σ(B)B' = \sigma_\ell(B),

AB=AB,PAB equals PAB (as corresponding angles).|A'B'| = |AB|, \qquad \angle PA'B' \text{ equals } \angle PAB \text{ (as corresponding angles)}.

In other words, reflection is a congruence transformation — it carries each figure as a whole to the other side of \ell, preserving lengths and angles.

Reflection schematic: a vertical axis \ell flips \triangle ABC to \triangle A'B'C'; the three horizontal dashed segments AA', BB', CC' are all perpendicularly bisected by \ell.

First 20 free · sign in for #21 onward

Sign in to unlock the full proof

The first 20 theorems are free to read; this one and the rest require an account to see the full proof, animation, and consequences. Free, email-code sign-in only.

Sign in to unlock
Help me make this theorem better