PRINCIPIA · THEOREM

In the same / equal circle: central angle / arc / chord are pairwise equivalent

Dependencies: Protractor axiom, SAS congruence.

Statement

Let O\odot O be a given circle of radius RR, with AA, BB, CC, DD on O\odot O. Consider the following three statements:

  1. Equal central angles: AOB=COD\angle AOB = \angle COD;
  2. Equal arcs: AB=CD\stackrel{\frown}{AB} = \stackrel{\frown}{CD} (subtended in the same orientation);
  3. Equal chords: AB=CD|AB| = |CD|.

In a single circle (or in two equal circles), these three statements are pairwise equivalent: any one implies the other two. Formally:

AOB=COD        AB=CD        AB=CD.\angle AOB = \angle COD \;\;\Longleftrightarrow\;\; \stackrel{\frown}{AB} = \stackrel{\frown}{CD} \;\;\Longleftrightarrow\;\; |AB| = |CD|.

Pairwise equivalence of equal central angles / equal arcs / equal chords in the same circle

First 20 free · sign in for #21 onward

Sign in to unlock the full proof

The first 20 theorems are free to read; this one and the rest require an account to see the full proof, animation, and consequences. Free, email-code sign-in only.

Sign in to unlock
Help me make this theorem better