PRINCIPIA · THEOREM

The difference of two sides is less than the third

Dependencies: Triangle inequality a + b > c (the sum of any two sides is greater than the third).

Statement

Let ABC\triangle ABC be any triangle, with sides a=BCa = BC, b=CAb = CA, c=ABc = AB. Then the absolute difference of any two sides is less than the third:

ab<c,bc<a,ca<b.|a - b| < c,\qquad |b - c| < a,\qquad |c - a| < b.

By symmetry it suffices to prove the first; the others follow by relabeling.

The difference of two sides is less than the third: lining up the three lengths, the "short stick" |a - b| is plainly shorter than c

10 foundational theorems free · one-time unlock for the rest

Unlock the complete proofs forever

Matching GeoSnap, 10 foundational theorems are completely free. Unlock every other proof, animation, and consequence with one $10 purchase.

Sign in to unlock
Help me make this theorem better