PRINCIPIA · THEOREM

Triangle area = ½ × base × height

Dependencies: Parallelogram area = base × height.

Statement

In ABC\triangle ABC, choose any side BCBC as the base, with length bb; from vertex AA drop a perpendicular foot HH onto line BCBC, and let AH=h|AH|=h be the corresponding height. Then the area of the triangle is

SABC  =  12bh.S_{\triangle ABC} \;=\; \tfrac{1}{2}\,b\,h.

Any of the three (base, height) pairs gives the same SSthe three base-times-height products are equal, a direct corollary of this formula.

Triangle \triangle ABC with base BC=b and height AH=h; area S=\tfrac{1}{2}bh.

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