PRINCIPIA · THEOREM

Rhombus area = ½ · d₁ · d₂

Dependencies: Rhombus: diagonals ⊥-bisect, Triangle area = ½ × base × height.

Statement

Let ABCDABCD be a rhombus with diagonals ACAC and BDBD, of lengths d1=ACd_1=|AC| and d2=BDd_2=|BD| respectively. They meet at a point OO. Then the area of the rhombus is

SABCD  =  12d1d2.S_{\diamond ABCD} \;=\; \tfrac{1}{2}\,d_1\,d_2.

Unlike a parallelogram or rectangle, whose area is usually expressed as base × height, the rhombus formula is written directly in terms of the two diagonals — so once the diagonals are measured, the area follows immediately.

Rhombus ABCD with diagonals d_1=AC, d_2=BD that perpendicularly bisect each other at O; area S=\tfrac{1}{2}d_1 d_2.

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