PRINCIPIA · THEOREM

Circumcircle of a triangle + circumcenter

Dependencies: three points determine a circle (Three non-collinear points determine a unique circle).

Statement

Let ABC\triangle ABC be any triangle. Then there is a unique circle passing through the three vertices AA, BB, CC, called the circumcircle of the triangle. Its center OO is called the circumcenter of ABC\triangle ABC, and the radius R=OA=OB=OCR = OA = OB = OC is called the circumradius:

OA  =  OB  =  OC  =  R.OA \;=\; OB \;=\; OC \;=\; R.

The circumcenter OO is at the same time the common intersection of the three Perpendicular bisector ⇔ equidistant from endpointss of the sides ABAB, BCBC, CACA (see Three perpendicular bisectors meet (circumcenter)).

Circumcircle of a triangle: the center O lies at the intersection of the three perpendicular bisectors, with the three radii OA=OB=OC=R.

First 20 free · sign in for #21 onward

Sign in to unlock the full proof

The first 20 theorems are free to read; this one and the rest require an account to see the full proof, animation, and consequences. Free, email-code sign-in only.

Sign in to unlock
Help me make this theorem better