PRINCIPIA · THEOREM

Angle bisector exists and is unique

Dependencies: Protractor axiom.

Statement

Let AOB\angle AOB satisfy 0<θ<1800^\circ < \theta < 180^\circ, where θ=AOB\theta = \angle AOB. Then inside AOB\angle AOB there exists a unique ray OCOC emanating from OO such that

AOC=COB=θ2.\angle AOC = \angle COB = \tfrac{\theta}{2}.

This ray OCOC is called the bisector of AOB\angle AOB.

Angle-bisector uniqueness: inside \angle AOB there is a unique ray OC that cuts \angle AOB into two equal halves \theta/2

Proof

Use only Protractor axiom: inside AOB\angle AOB, sweeping counterclockwise around OO from OAOA to OBOB, each φ(0,θ)\varphi\in(0,\theta) corresponds uniquely to an interior ray OCφOC_\varphi with AOCφ=φ\angle AOC_\varphi = \varphi (the protractor gives a bijection between (0,θ)(0,\theta) and the interior rays of AOB\angle AOB).

Existence: take φ=θ/2(0,θ)\varphi = \theta/2 \in (0,\theta) and call the corresponding ray OCOC. Then AOC=θ/2\angle AOC = \theta/2, so COB=θθ/2=θ/2=AOC\angle COB = \theta - \theta/2 = \theta/2 = \angle AOC.

Uniqueness: if some other ray OCOC' also bisects AOB\angle AOB, i.e. AOC=COB\angle AOC' = \angle C'OB, then 2AOC=θ2\angle AOC' = \theta, so AOC=θ/2=AOC\angle AOC' = \theta/2 = \angle AOC. By the injectivity of the protractor, the same angle value corresponds to the same interior ray, so OC=OCOC' = OC. \qquad\blacksquare

Step 1: the protractor pins down OC at \varphi = \theta/2 (existence); any alternative OC' is squeezed back to the same OC via "2\angle AOC' = \theta" (uniqueness)

Immediate consequences

  • Isoceles: median, altitude, bisector coincide reduces the "apex-angle bisector" to this unique ray, and then by symmetry shows it is simultaneously the median and altitude to the base.
  • In the argument that the three angle bisectors of a triangle meet at a point (triangle Three angle bisectors meet (incenter)), "the bisector" of each interior angle is the unique object provided by this theorem — without it, "three lines concurrent" cannot even be stated cleanly.

Remarks

The proof contains no figure manipulation: no folding, no rotation to overlay AOC\angle AOC onto COB\angle COB. We simply translate the geometric condition "bisection" into the numerical condition "angle measure equals θ/2\theta/2", and then invoke the bijectivity of the protractor. This is the immediate dividend of Protractor axiom having algebraised "angle" — many arguments that appear to require "moving" pieces around are in fact just a single substitution.

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