PRINCIPIA · THEOREM

Geometric mean / altitude-on-hypotenuse theorem

Dependencies: AA similarity.

Statement

Suppose ABC\triangle ABC has a right angle at CC, i.e. C=90\angle C = 90^\circ. Denote the three sides by a=BCa = BC, b=CAb = CA, c=ABc = AB. Drop a perpendicular from the vertex CC to the hypotenuse ABAB, with foot HH, i.e. CHABCH \perp AB at HH.

Then the altitude CHCH to the hypotenuse splits the right triangle ABC\triangle ABC into two small triangles similar to the original:

ACH    CBH    ABC.\triangle ACH \;\sim\; \triangle CBH \;\sim\; \triangle ABC.

From this triple similarity one immediately reads off three length identities — together they are called the altitude-on-hypotenuse theorem:

a2=cHB,b2=cAH,CH2=AHHB.a^{2} = c\cdot HB,\qquad b^{2} = c\cdot AH,\qquad CH^{2} = AH\cdot HB.

The first two say "the square of each leg equals its projection onto the hypotenuse times the whole hypotenuse"; the third says "the altitude to the hypotenuse is the geometric mean of the two segments into which the hypotenuse is divided".

Altitude-on-hypotenuse: \triangle ACH \sim \triangle CBH \sim \triangle ABC, giving a^2 = c\cdot HB, b^2 = c\cdot AH, CH^2 = AH\cdot HB

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