PRINCIPIA · THEOREM

Inscribed angles on the same arc are equal

Dependencies: Central angle is twice the inscribed angle on the same arc (inscribed angle = half the central angle).

Statement

Let a chord ABAB on O\odot O divide the circle into two arcs. Fix one of the arcs — call it the "other arc" — and on the remaining arc take any number of points PP, QQ, RR, …. Then the corresponding inscribed angles are all equal:

APB  =  AQB  =  ARB  =  \angle APB \;=\; \angle AQB \;=\; \angle ARB \;=\; \cdots

In other words, as long as the vertex moves along the same arc, the inscribed angle subtended by chord ABAB is a constant independent of the vertex's position.

Inscribed angles on the same arc are equal: chord AB + multiple points P, Q, R on the arc; the inscribed angles \angle APB = \angle AQB = \angle ARB at the three positions are all equal

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